//Idea:  given array with duplicates (or not)  print out duplicate numbers

#include <iostream>

#include <sstream>

#include <algorithm>

#include <vector>

using namespace std;

#define FOR(i,n) for (int i=0;i<(int)n;i++)

#define FORN(i,a,b) for (int i=a;i<=(int)b;i++)

int main()

{

      int n;

      vector<int> v,r;

      while (cin>>n && n!=0)

      {

            v.clear();

            r.clear();

            v.resize(n);

            FOR(i,n) cin>>v[i];

            sort(v.begin(),v.end());      //sort!

            int prev=0;

            FOR(i,v.size()-1)

            {

                  if (v[i]==v[i+1])

                  {

                        //first time duplicate is detected

                        //and we record it in "prev"

                        prev=v[i];                   

                  }

                  else

                  {    

                        //no more duplicates are detected!

                        if (prev>0) //if there was a duplicate, we store it

                        {

                              r.push_back(prev);

                              prev=0;     //and reset, so we don't add it again

                        }

                  }          

            }

            //check if any unrecorded duplicates got left over

            //i.e. last two numbers in array were the same

            //so we could not get to them in the loop above

            if (prev>0) //for previous duplicate

            {

                  r.push_back(prev);

            }

            if (r.size()>0)

            {

                  cout<<r.front();

                  FORN(i,1,r.size()-1) cout<<" "<<r[i];

            }

            else cout<<"I want more dogs with large eyes!";

            cout<<endl;

      }

      return 0;

}